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Will global warming change the average air pressure?

I look after a pendulum clock at the University of Cambridge which I hope will achieve an accuracy of less than 1 second of error per year (www.trin.cam.ac.uk/clock). It has a temperature-compensated pendulum, but is sensitive to air pressure variation.

If the mean global temperature was to rise by, say, 4 °C, would there be any change to mean air pressure at sea level? Put simply, would global warming cause the clock to speed up or slow down?

Hugh Hunt, Keeper of the Clock, Trinity College, University of Cambridge, UK

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Categories: Planet Earth, Weather , Unanswered.

Tags: temperature, climatechange, globalwarming, clock, airpressure.

 

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Jon-Richfield says:

The mean air pressure at sea level is most simply a function of the mass of the atmosphere. This in turn is a function of two components, the mass of each molecule in the atmosphere and the number of molecules of any given mass. By heating or cooling any particular volume of the atmosphere we cause transient local pressure changes as a result of expansion and convection, but no significant effect on mean air pressure. If global warming were to cause a marked increase in extremes of weather, that certainly might affect your clock, though obviously not in any consistent direction.

There is however another factor. Higher temperatures might be expected to increase the volatility of many substances on the planet, of which far and away the major example would be water. For example if a great deal of water were to evaporate from the mid-latitudes and precipitate as ice in the polar latitudes, this might start a positive feedback cycle reducing mean atmospheric humidity. In other words there would be less atmosphere and mean pressure would drop. Conversely, if increasing amounts of water were to remain in the atmosphere, mean atmospheric pressure would indeed increase.

Increasing the mass of molecules, eg by replacing oxygen with carbon dioxide would increase the pressure, but at a few hundred parts per million, the increase would require some very sensitive measurement to detect it!

I love the sound of your clock!

 

Jon

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posted on 2010-02-03 19:38:07 | Report abuse


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thejll says:

 

If atmospheric warming does not alter the mass of the atmosphere and provided gravity does not change then the sea-level pressure will be about 101325 Pascals, no matter what the atmospheric temperature is so that sea-level pendulum clocks will not experience any more air-friction than before. What will happen is that the atmosphere expands as it warms and this will cause a rise in air-pressure at a fixed height above sea-level – say, up a mountain. This happens because a larger fraction of the atmosphere will be above the fixed height, causing a greater pressure than before to be recorded. In fact, this idea has been used to show that the thermometer-based estimates of temperature changes through the 20th century are correct – a temperature-estimate based on records of mountain-station barometer readings, and sea-level pressures showed the same pattern as thermometer readings – warming to the 1940’s, cooling to about 1970 and warming since then.

However, rigorously and in reality, as a warmer atmosphere does hold more moisture the mass of the atmosphere will increase with warming and thus even sea-level pressures will rise a bit and friction on the pendulum clocks of the world will increase, slowing them down a bit.

 

 

Peter Thejll, Danish Climate Centre.

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posted on 2010-02-05 16:21:33 | Report abuse

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Jon-Richfield says:

Nice one Peter! I had not thought of altitude.  ;-(

And besides, of course, even Cambridge is slightly above sea level -- for now!

Thanks,

 

Jon

 

 

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posted on 2010-02-06 06:24:16 | Report abuse

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Pedant says:

It's the increased buoyancy of the pendulum bob and increased mass of moving displaced air which slow the clock in denser air. Friction should have little effect with a properly designed escapement but can slow or speed up a clock with a poorly designed or badly adjusted escapement.

With a high quality "dead-beat" escapement, any extra friction would tend to reduce the amplitude of the pendulum's swing. This would speed up the clock by about 20 seconds per year per degree of amplitude per arcminute reduction in amplitude.

 

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posted on 2010-02-09 16:54:06 | Report abuse


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quatra says:

You say it's sensitive to air pressure, so I'd worry about the normal variations in barometric pressure.

 

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posted on 2010-02-08 23:07:25 | Report abuse


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Moderator says:

The accuracy of a pendulum clock is affected by changes in the density of the air surrounding the pendulum. That's because the air exerts a slight buoyant force on the bob, counteracting the downward pull of gravity, while friction between the bob and the air effectively increases its mass. Both effects slow down the clock, the degree of slowing being dependent on the density of the bob and also its shape. A typical pendulum clock might lose around 40 seconds per year for a 1 per cent increase in air density.

The density of air depends on its temperature and pressure, and on the average molecular weight of the gases that make it up. A reduction in temperature from 20 °C to 19 °C will increase air density by about 0.34 per cent and so slow the clock by some 14 seconds per year. We do not need to concern ourselves with this, however, as it is taken into account in the way a clock pendulum is temperature-compensated to minimise the effect of thermal expansion.

A pressure increase of 1 millibar (100 pascals) increases air density by 0.1 per cent and slows the clock by about 4 seconds per year. Some clocks have a barometric compensation device built into the pendulum and some are even put inside isobaric chambers to avoid the problem altogether.

The main source of variability in the average molecular weight of air is its water vapour content. At 16 °C, a rise in relative humidity (RH) from 30 to 40 per cent would reduce air density by 0.07 per cent and speed up the clock by some 3 seconds per year.

If we keep RH constant, we would find the amount of water vapour that air can hold nearly doubles for every 10 °C rise in temperature. If the whole atmosphere warmed by 4 °C, its water-vapour content would increase by around 30 per cent, assuming no change in RH overall. This would increase the total mass of the atmosphere and the pressure at sea level would rise by about 0.7 millibars, which would slow the clock by about 3 seconds per year.

However, this would be offset by an increase in the RH of the clock's local environment, which is likely to occur unless air-conditioning is used. The increase in RH at fixed temperature mentioned above would exactly cancel out the previous effect.

As is so often the case, the answer to the question is really "it depends".

Chris Terry, Teddington, Middlesex, UK

 

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posted on 2010-11-03 15:21:44 | Report abuse

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Pedant says:

I didn't think I'd ever find it necessary to reply to my own answer, but Moderator has not so much edited it as completely rewritten it! I didn't think my style or grammar were that bad and Moderator's version is longer than mine. 

Moderator has also introduced a glaring error for good measure! In the first paragraph of my actual answer below, I do not say anything about air friction because it is largely irrelevant (see my reply to Thejll above). Moderator has misconstrued my mention of the boundary layer as a reference to friction! In fact, the slowing effect referred to is due to the mass of the displaced air moving in the opposite direction to that of the pendulum and has nothing to do with friction.

Here is my original submission:-

"The accuracy of a pendulum clock is affected by the density of the air surrounding the pendulum. Air density depends on atmospheric temperature, pressure and average molecular weight. Buoyancy reduces the total downward force on the bob and the boundary layer of air moved by the bob effectively increases its mass. Both of these effects slow down the clock. The amount of slowing depends on the density of the bob and also on its shape in the case of the boundary layer effect but a typical pendulum clock might lose around 40 seconds per year for a 1% increase in air density.

A 1 Celsius reduction in temperature increases air density by about 0.34% at 20 Celsius and so slows the clock by some 14 seconds per year. This is allowed for in the amount of temperature compensation which is routinely applied to pendulums to reduce the effect of thermal expansion of the pendulum rod.

A pressure increase of 1 millibar increases air density by 0.1% and therefore slows the clock by about 4 seconds per year. Some clocks have a barometric compensation device built in to the pendulum and some have even been put inside isobaric chambers to avoid the problem altogether.

The main variability in the average molecular weight of air comes from the water vapour content which is exponentially related to temperature nearly doubling for each 10 Celsius temperature rise at constant relative humidity (RH). At 16 Celsius a change from 30% to 40% RH would cause a reduction in air density of 0.07% and speed up our clock by some 3 seconds per year.

As for the 4 Celsius temperature rise, if this were applied to the whole of the atmosphere, its total water vapour content would increase by around 30% assuming the same RH profile. This would increase the total mass of the atmosphere and the pressure at sea level would rise by about 0.7 millibar which would slow the clock by about 3 seconds per year.

However, this would be offset if the humidity of the clock's local environment were to increase which is likely unless air conditioning is used. The RH example described above would exactly cancel out the pressure effect and a greater or lesser change would result in a respectively fast or slow clock.

As is so often the case, the answer to the question is "it depends".

Chris Terry, Teddington, Middlesex, UK"

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posted on 2010-11-04 20:50:28 | Report abuse


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