I have been having bad luck with duplicates lately. Pity me...

No. The wall does not contribute a significant amount of energy. The oncoming car does. You would have to hit the wall at double the speed to get a comparable effect.

Don't try this at home!

The energy in a moving mass is half the mass times the square of the speed.  Look it up in an introductory physics textbook to find a full explanation.

Jon

A head-on crash into an identical car moving at the same speed in the opposite direction will stop your car dead (no pun intended), just like driving into a brick wall, and it will have the same effect.  But a head-on crash into a much heavier vehicle moving in the opposite direction will shunt what's left of your car backwards; the change in velocity, and hence acceleration of your car will be greater, and the damage will be greater.  If you have a head-on with a lighter car moving at the same speed, you'll continue to move in the same direction at a reduced speed, so the damage to you will be less. 

@jon if so then wouldn't you need to travel at x 2^1/2 the speed to have the same energy

It would only be true that the result would be identical if the wall were such an ideal immoveable object that it absorbed no energy from the car.

In that case, the two car crash could be said to be equal, because each car would absorb the same amount of energy, and this would be the same as a single car absorbing all its own inertia.

If the wall is not ideal, then there is a difference, as the wall absorbs some of the car's inertia.

To help decide whether the energy matters or not, have someone gently lay the palm of their hand along the side of your face for a moment.

 Then have them put the same hand on the same part of your face, this time including a high amount of momentum.