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WHY do some chemical reactions of two colourless reagents produce a product with colour?

Eg: N2(colourless gas)+O2(colourless gas)=NO2(brown coloured gas)

 

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  • Asked by l3irus
  • on 2010-11-30 23:08:19
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Last edited on: 2010-12-01 12:29:49

Categories: Unanswered.

Tags: colour, chemistry, science, experiment, chemicalreaction.

 

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MikeAdams#367 says:

The quick answer (Jon can provide a more detailed one) is that some chemical bonds will absorb specific wavelengths of light, while others don’t. In your example neither of the starting compounds absorb significantly in any of the visible wavelengths but the product does. 

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posted on 2010-12-01 17:59:41 | Report abuse


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Georg says:

There is no "more detailled" answer.

Some materials absorb (part) of the visible light,

being colored for this reason.

This is a property of that material, regularly not

"inherited" from the ingredients the material was

made of.

Georg

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posted on 2010-12-01 20:18:32 | Report abuse


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Jon-Richfield says:

Why pick on me?

Oh well, let's have a go!  

Suppose you have a suitable polished rectangular metal bar, possibly drifting in free fall in a cabin in Spacelab.

Suppose you strike the bar near its middle with a suitable hammer.

The bar vibrates, giving off a particular note. Let us suppose (since we are doing a a lot of supposing) that the note has a frequency of 256 Hz.

Now what part of the bar was responsible for the note? If you examine the bar in vibration, you typically will find that the two ends move in one direction while the middle moves in the opposite direction and then they reverse their motion 512 times a second.

You cannot really say that any one part of the bar was responsible; it all followed from the shape of the entire bar and the material it is made of. Change the shape and you will change or abolish the note it gives off when struck, or make it give off several notes Change the material, and the note will change, or even vanish. Cotton wool for example will not give you much of a note.

Very well then; in an analogous way, a molecule of a coloured substance will either pass or generate or absorb a photon of a particular colour (frequency), depending on  the structure of that molecule. As Mike and Georg variously pointed out, you have to look at the whole molecule; you cannot break the molecule apart and expect to get half of the colour from one part and half from another.

Generally a coloured molecule will contain at least two parts, joined by bonds that act as a springy hinge that permit the molecule to vibrate about that bond, much as our bar vibrated about its middle. The frequency of that vibration is what determines the colour of the molecule. If I take two atoms of oxygen and attach them by double bonds to each side of one atom of nitrogen, giving me a molecule of NO2, then they can vibrate about the nitrogen atom in a few ways that in combination produce that handsome redbrown colour.

The vibrations of 02 and of N2 do also happen, but their colours are not visible to the human eye, so we see their gases as colourless. In much the same way, if we break that bar of ours down far enough, some of the notes it gives off will be ultrasonic and we might not be able to hear its vibrations at all.

Yet again, an atom of say helium, doesn't have a great deal of freedom to vibrate in any such mode at all; it does not have the necessary parts.

You might well ask then, why, if NO2 gives us that nice redbrown, CO2, which has roughly the same shape, does not?

It is simply that CO2 is not tuned to vibrate at any frequency that we can see, and in fact most common gas molecules are not tuned to visible colours either. So to get back to your original question, the fact that oxygen and nitrogen do or do not vibrate in a suitable way to produce or pass light that you can see, has nothing to do with the fact that atoms of oxygen and nitrogen can be joined to make a molecule that does in fact pass redbrown light.

I hope that helps, but this is very much a handwaving description of a complex and mathematical set of principles. If part of it seems to make no sense, feel welcome to ask more, but we cannot of course promise to cover the whole matter here.

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posted on 2010-12-02 13:30:47 | Report abuse

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Georg says:

Hello Jon,

that wasn't aimed as a pick on You, more on MikeAdams.

Problem: when You tried to explain "Reason" for color,

You made a mistake: vibrational transitions are

located in the infrared solely.

Optical transitions (i.e. from about 1 µm to Roentgen waves)

are due to lifting up (and falling back down) of electrons

between electronic levels in the molecule/átom.

No "vibrations"there :=(

(Not even "Good Vibrations")

The main problem with the question remains:

Color in a molecule is not inherited from the "parents".

The way by which a certain  molecules gets his  colour

is much too complicated to explain to someone not knowing MO

or some other appropriate theory of molecular binding.

So, one can only say: not from the reactants!

Georg

 

 

 

 

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posted on 2010-12-03 15:32:51 | Report abuse

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Jon-Richfield says:

Hi Georg,

This thread is dogged by confusion! When I said "Why pick on me?" I intended addressing Mike because I am no chemist. Life is full of complications!  :-) Anyway, it would hardly have mattered if I had been addressing you, because I meant it humorously.  ;-)

Notice one way or another that the three of us all agreed on the effective answer and tried to explain as kindly as might be, that one could not generally expect to get half a colour out of half a molecule, any more than one could expect to get half a square out of two sides instead of four.

 

You said: >Problem: when You tried to explain "Reason" for color, You made a mistake: vibrational transitions are located in the infrared solely. Optical transitions (i.e. from about 1 µm to Roentgen waves) are due to lifting up (and falling back down) of electrons between electronic levels in the molecule/átom.  No "vibrations"there :=(     <

I have a bit of a problem with that, in particular with your use of the word "solely". The ends of the  regions you mention are not sharp; I cannot give you a specific reference off hand to the absorption spectrum of NO2 and it sources, but I have a memory that its vibrational and electronic spectra overlapped, which is plausible, looking at its stiff structure. (You will notice that the colour of NO2 is far into the red-brown.) But in context it would not have been easy to explain the half-molecule or molecular constituents idea in terms of orbitals, either molecular or atomic, as I am sure you would agree!  :-)

 

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posted on 2010-12-10 20:27:05 | Report abuse


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