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In the following example at what angular speed does gravity behave incorrectly?

If three bodies each move at constant angular speed, each following a trajectory given by r=R.(1+K.cos(A+n.120)) and each of these bodies rotates about its own axis in a manner that balances out the torque variation due to radial change, what angular velocity must the system rotate at before a gravitational force starts to be resolved at the system reference point in the direction A=0?

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  • Asked by akb
  • on 2011-01-24 09:34:53
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Categories: Our universe.

Tags: relativity, gravity.

 

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Jon-Richfield says:

Would you care to elucidate before you ask us to excogitate? So far I think I understand that we are contemplating three hypothetical bodies; unless I have misunderstood, you need not elaborate on that part. It is the other half that I can make nor sense nor substance of.

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posted on 2011-01-24 11:50:32 | Report abuse


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Georg says:

I'll try some

"educated" guesses :=)

The tree bodies circle around a common point, with

the same distance to that point, and a phase of

120 °.

In other words, the three bodies are located at the corners of a

equilateral triangle and the the triangle rotates with some

speed not given. Mass of that bodies is not given as well.

THis btw is a at best a metastable trajectory in case the bodies

have identical masses, otherwise the trajectory is unphysical. 

Now the strange part: akb surmises, that some rotation of those

bodies about their own axis has some influence on the

trajectories. This is not the case. Even in GR that would be second

or third order correction

Georg

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posted on 2011-01-24 21:17:49 | Report abuse


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Paul_Pedant says:

I suspect this is a spoof whose origins go back to conjectures about how Flying Saucers might attain momentum without a reactive force.

These guys in Arizona are urgently trying to raise funds to complete their anti-gravity drive, which is based on -- a rotating equilateral triangle of gyroscopes.

I think we should all support them to the maximum amount that this research deserves. This could be a really significant development.

http://www.ganid.com/

 

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posted on 2011-01-25 22:37:08 | Report abuse


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akb says:

Clarification. The three bodies are not equidistant from the central axis. But move following the relation r=R(1+kcos(A)). The angular speed remains constant, radius varies.

Due to the variation in radius the torque associated with each body is countered by the individual body oscillating at  about its own axis

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posted on 2011-01-30 23:04:52 | Report abuse


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Paul_Pedant says:

This is just unscientific claptrap.

Just what does the phrase "gravity behave incorrectly" mean? What grounds or evidence would you have for that assumption, and against what standards are you defining "incorrectly". Is it passing the port to the left after dinner? Is it emitting detectable gravitons? Is it mysteriously rising off the table. I think we should be told.

You say "The angular speed remains constant, radius varies." No, it does not - ask any ice skater. The angular momentum remains constant (unless you are stuffing external energy into the system). So any mass that is suddenly pulled in to a smaller radius for a part of its revolution would merely be forced to rotate faster than those other elements at different radii, and would distort the apparatus.

I offer the below link as a possible  implementation of the mechanism you describe. It, too, appears to be a collection of balls.

http://cart.clockparts.com/rotary-pendulum-drive-p-188.html

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posted on 2011-01-30 23:53:39 | Report abuse


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